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March 5, 2015

March 5, 2015

Posted by **Jasmin** on Wednesday, March 30, 2011 at 5:55am.

- Calculus -
**drwls**, Wednesday, March 30, 2011 at 6:27amThe epidemic is a maximum when

dN/dt = 0

dN/dt = [-5t*(2t) + 5(12 + t^2)]/(12 + t^2) = 0

That will be zero when the numerator is zero, so

-10t^2 + 60 + 5 t^2 = 0

t^2 = 12

t = 3.46 weeks

N(3.46) = 17.3/23.97 = 0.748 hundred new cases (75 cases)

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