Posted by **Lace** on Wednesday, March 30, 2011 at 1:32am.

This problem has been very hard for me. I would appreciate it if someone could maybe help..

Solve: 2a - b = ac + 3b for a

I came up with a = c + 4b but I really don't know..

- Algebra -
**Jai**, Wednesday, March 30, 2011 at 1:54am
2a - b = ac + 3b

to get a, first we need to transpose all terms containing a to one side of equation, and all other terms to the other side,, in this case the terms containing a are 2a and ac. let's just transpose them to the left side of equation,,

since ac is on the right and we wish to transpose it to the left side, we change its sign from positive to negative:

2a - b = ac + 3b

2a - b - ac = 3b

we do the same for -b. -b becomes +b if transposed to other side:

2a - ac = 3b + b

now we factor a from 2a - ac:

a(2 - c) = 3b + b

also, we can combine 3b and b:

a(2-c) = 4b

now to get a alone, we divide both side of equation by (2-c):

a(2-c)/(2-c) = 4b/(2-c)

a = 4b/(2-c)

hope this helps~ :)

- Algebra -
**Lace**, Wednesday, March 30, 2011 at 2:05am
Oh, wow, this does help! Fast response and detailed explanation.

Thank you so much, appreciate it.

Have a good one!

## Answer This Question

## Related Questions

- Basic Algebra - I am having a hard time trying to figure out this problem, if ...
- math - how would you solve for y in this problem: x=(y^2+3y)^(1/3) would it ...
- algebra - Solve the system using elimination X+3y=5 4x+4y=4 I tried to work this...
- algebra 2 - i need help with my algebra 2 homework, the section is called using ...
- Algebra 2 - I would really appreciate it someone helped me with this information...
- Algebra 2 - Solve and Graph: ( i know that second part would be difficult but ...
- math - Can someone please show me step by step how to solve this, I've been ...
- Algebra 1 - Can someone simply tell me what methods I must use in order to ...
- Algebra 1 - Can someone simply tell me what methods I must use in order to ...
- Algebra again - I don't understand how to do this problems: Solve for the ...

More Related Questions