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April 17, 2014

April 17, 2014

Posted by **Michelle** on Tuesday, March 29, 2011 at 11:52pm.

- Math -
**Jai**, Wednesday, March 30, 2011 at 2:16amfirst recall that perimeter of a rectangle is

P = 2(L+W)

where

L = length

W = width

substituting,

12 = 2(L+W)

6 = L+W

now we need to find for positive, nonzero integers whose sum is 6,, the possible values are:

L=5 and W=1

L=4 and W=2

L=3 and W=3 (this is a square but note that square is also a rectangle)

hope this helps~ :)

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