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March 30, 2015

March 30, 2015

Posted by **Student in Need** on Tuesday, March 29, 2011 at 1:16pm.

I thought the answer would be 48dB's but that would be way to high? How would you explain how to get the answer to someone with no experience in physics and how to get the answer?

- physics -
**drwls**, Tuesday, March 29, 2011 at 4:33pmThe sound power will be reduced to 40% of the original value.

Sound is measured in logarithmic units of decibels. 10 dB are a factor of 10 in power. In this case, the sound power is reduced not that much.

In your case,

dB reduction = 10 Log(10)2.5 = 4.0 dB

The new reading will be 116 dB

- physics -
**Student in Need**, Tuesday, March 29, 2011 at 4:48pmHow are you getting 40%? Were does the 2.5 come from? I did this calculation on my calculator (the log part) and it came out to 25?

- physics -
**cindy**, Thursday, March 5, 2015 at 2:56pm40% because the quiet number is 60%, so the ones are really making noise are the 40%. and 2.5 is because 100 divide by 40 would be 2.5

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