Posted by Student in Need on Tuesday, March 29, 2011 at 1:16pm.
The sound power will be reduced to 40% of the original value.
Sound is measured in logarithmic units of decibels. 10 dB are a factor of 10 in power. In this case, the sound power is reduced not that much.
In your case,
dB reduction = 10 Log(10)2.5 = 4.0 dB
The new reading will be 116 dB
How are you getting 40%? Were does the 2.5 come from? I did this calculation on my calculator (the log part) and it came out to 25?
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