We're in class with a SIL decibel meter up front, and everyone is screaming at the top of their lungs, hooting and shouting and pounding on their desks, shooting off firecrackers, its Phys 1240 gone wild...and the meter is reading a reasonably steady sound intensity level of 120 dB. At a pre-arranged signal from Professor Parker, sixty (60) percent of the class suddenly gets totally quiet, while the remaining students continue making the same noise. What sound intensity level would the meter now show?

I thought the answer would be 48dB's but that would be way to high? How would you explain how to get the answer to someone with no experience in physics and how to get the answer?

The sound power will be reduced to 40% of the original value.

Sound is measured in logarithmic units of decibels. 10 dB are a factor of 10 in power. In this case, the sound power is reduced not that much.

In your case,
dB reduction = 10 Log(10)2.5 = 4.0 dB

The new reading will be 116 dB

How are you getting 40%? Were does the 2.5 come from? I did this calculation on my calculator (the log part) and it came out to 25?

40% because the quiet number is 60%, so the ones are really making noise are the 40%. and 2.5 is because 100 divide by 40 would be 2.5

To determine the sound intensity level after 60% of the class gets quiet, we need to understand how sound intensity levels combine when different sound sources are present.

In this case, we have two different sound sources: the 60% of the class that becomes quiet (which we'll call "source A") and the remaining noisy students (which we'll call "source B").

The sound intensity level (SIL) is measured on a logarithmic scale in decibels (dB). When combining two or more sound sources, we use a formula known as the decibel addition rule:

SIL_total = 10*log10[(10^(SIL_A/10)) + (10^(SIL_B/10))]

Now, let's use this formula to find the new sound intensity level.

Initially, both source A and source B were producing the same sound intensity level of 120 dB. However, now only 40% of the class is making noise (source B), while 60% becomes quiet (source A).

To find out the sound intensity level of source A, we can use the given information that 60% of the class is quiet. So, the noise level due to source A becomes 0 dB because it is completely silent.

Now we substitute the values into the decibel addition rule:

SIL_total = 10*log10[(10^(0/10)) + (10^(120/10))]

Simplifying the equation:

SIL_total = 10*log10[1 + 10^12]

Using a calculator to compute 10^12:

SIL_total = 10*log10(1 + 10^12) = 10*log10(1 + 1,000,000,000,000)

The result is approximately 120.08 dB.

Therefore, the sound intensity level shown on the meter after 60% of the class gets quiet would be about 120.08 dB, which is slightly higher than the initial 120 dB level but not significantly different.