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March 29, 2017

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A store sells televisions for $360 and video cassette recorders for $270. at the beginning of the week its entire stock is worth $45,990. During the week it sells three quarters of the televisions and one third of the video cassette recorders for a total of $27,630. How many televisions and video cassette recorders did it have in its stock at the beginning of the week?

  • math i need help plz! - ,

    You need to write two equations in two unknowns, and then solve for them both.
    Let x be the original number of TVs and y be the original number of VCRs.

    Here is what you know:
    360 x + 270 y = 45,990
    (3/4)*360 x + (1/3)*270 y = 27,630
    which can be simplified to:
    270 x + 90 y = 27,630

    Tripe the last equation and subtract the first.

    810 x + 270 y = 82,890
    360 x + 270 y = 45,990
    ______________________
    450 x = 36,900
    x = 820

    Use any of the original equations to solve for y.

  • math i need help plz! - ,

    I've been working on this for a while but I cant seem to get anywhere with this. I created this equation.

    360(x) + 270 (y) = $ 45,990
    360 (3x/4) + 270 (x/3) $27, 630

    There's a starting point. If I figure out how to solve this I'll post.

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