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September 2, 2014

September 2, 2014

Posted by **lulu** on Monday, March 28, 2011 at 8:44pm.

- math -
**Reiny**, Monday, March 28, 2011 at 9:28pmmake a diagram

let the base be BC, where angleB= 37 and angle C = 33°

From the top vertex A drop an altitude to meet BC at D

let AD = h, BD = x, then DC = 1.75-x

you now have two right-angled triangles

from ABD,

tan 37 = h/x

h = xtan37

from ADC

tan 33 = h/(1.75-x)

h = tan33(1.75-x)

then x tan37 = 1.75tan33 - xtan33

xtan37 - xtan33 = 1.75tan33

x(tan37-tan33) = 1.75tan33

x = 1.75tan33/(tan37-tan33)

once you have that evaluated, put that x value into

h = xtan37

you do all the button-pushing.

- math -
**lulu**, Saturday, July 21, 2012 at 12:21pmi got up to the very last step but when i plugged my x value into h=xtan37 i just got decimals, like .97131.. what is the answer supposed to be?

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