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March 3, 2015

March 3, 2015

Posted by **Robbie** on Monday, March 28, 2011 at 5:32pm.

allen has nickels dimes and quarters in his pocket. the number of nickels is 1 more than twice the number of quarters. the number of dimes is 1 less than the number of quarters. if the value of change in his pocket is 85 cents, how many of each coin does he have?

- math -
**Reiny**, Monday, March 28, 2011 at 5:43pmnumber of quarters = x

number of nickels = 2x+1

number of dimes = x-1

now use the "value" of those coins to get

25x + 5(2x+1) + 10(x-1) = 85

should be pretty easy to solve

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