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can someone help explain how to do this?
allen has nickels dimes and quarters in his pocket. the number of nickels is 1 more than twice the number of quarters. the number of dimes is 1 less than the number of quarters. if the value of change in his pocket is 85 cents, how many of each coin does he have?

  • math -

    number of quarters = x
    number of nickels = 2x+1
    number of dimes = x-1

    now use the "value" of those coins to get
    25x + 5(2x+1) + 10(x-1) = 85

    should be pretty easy to solve

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