Posted by **Anonymous** on Monday, March 28, 2011 at 5:19pm.

Theresa has $26 in her wallet. The bills are worth either $5 or $1. If there are 14 bills total, how many does she have of each type?

- algebra -
**E***, Monday, March 28, 2011 at 5:28pm
Set up your given:

Let x be $5

Let y be $1

Amount: 5x + y = 26

Number of bills: x + y = 14

Solve the equations by elimination:

(multiply the first equation by -1 to make y negative.. it would then cancel out)

-5x - y = -26

x + y = 14

-4x = -12

x = 3

Plug in x to any of your orig. equations

x + y = 14

$5 = 3

$1 = 14-3

= 11

Check: 3 $5 bills and 11 $1 bills equal to 14 bills.

Check: 3x$5 = $15

11x$1 = $11

$15 + $ 11 = $26

- algebra -
**sarah**, Thursday, March 17, 2016 at 7:45pm
Is it 3 fives and 11 ones

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