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April 20, 2014

April 20, 2014

Posted by **Anonymous** on Monday, March 28, 2011 at 4:39pm.

- Calculus -
**Reiny**, Monday, March 28, 2011 at 4:48pmthe height relative to the ground will be

s(t) = 16t^2 + 90t + 100

a)

s'(t) = -32t + 90

= 0 for max of s(t)

32t = 90

t = 90/32 = 2.8125 seconds

b)

ball hits the ground when s(t) = 0

-16t^2 + 90t + 100=0

8t^2 - 45t - 50 = 0

solve for t using the quadratic formula , refect the negative result

- Calculus -
**Anonymous**, Monday, March 28, 2011 at 8:48pmShouldn't 90t be 96t since 96 feet/second is the velocity?

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