Post a New Question

Calculus

posted by on .

A ball is thrown upward with an initial velocity of 96 feet per second from the top of a 100 foot building. (a) When well the ball attain its maximum height? (b) When will the ball hit the ground? Give a decimal answers correct to 2 decimal places.

  • Calculus - ,

    the height relative to the ground will be
    s(t) = 16t^2 + 90t + 100

    a)
    s'(t) = -32t + 90
    = 0 for max of s(t)
    32t = 90
    t = 90/32 = 2.8125 seconds

    b)
    ball hits the ground when s(t) = 0
    -16t^2 + 90t + 100=0
    8t^2 - 45t - 50 = 0

    solve for t using the quadratic formula , refect the negative result

  • Calculus - ,

    Shouldn't 90t be 96t since 96 feet/second is the velocity?

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question