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April 1, 2015

April 1, 2015

Posted by **Anonymous** on Monday, March 28, 2011 at 4:39pm.

- Calculus -
**Reiny**, Monday, March 28, 2011 at 5:03pmV = (4/3)πr^3

dV/dt = 4πr^2 dr/dt (#1)

when 4πr^2 = 2π

r^2 = 1/2

r = 1/√2

in #1:

10 = 4π(1/√2)^2 dr/dt

10= 2π dr/dt

dr/dt = 5/π or 1.592 inches/sec

check my arithmetic

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