The participants in a weight-loss class lost the following weights (in pounds) after three weeks of dieting:3,6,0,3,0,0



Assuming that these weights constitute an entire population, find the standard deviation of the population. Round your answer to at least two decimal places.

(If necessary, consult a list of formulas.)
I am coming up with the answer 21.0 but my study partner says it is still wrong can someone help me

To find the standard deviation of a population, you can follow these steps:

1. Calculate the mean of the population. To do this, sum up all the weights and divide by the total number of weights.

Mean = (3 + 6 + 0 + 3 + 0 + 0) / 6 = 12 / 6 = 2

2. Calculate the deviation of each weight from the mean. This is done by subtracting the mean from each weight.

Deviation = (3 - 2), (6 - 2), (0 - 2), (3 - 2), (0 - 2), (0 - 2) = 1, 4, -2, 1, -2, -2

3. Square each deviation. This is done by multiplying each deviation by itself.

Deviation Squared = 1^2, 4^2, (-2)^2, 1^2, (-2)^2, (-2)^2 = 1, 16, 4, 1, 4, 4

4. Calculate the variance. This is done by summing up all the squared deviations and dividing by the total number of weights.

Variance = (1 + 16 + 4 + 1 + 4 + 4) / 6 = 30 / 6 = 5

5. Calculate the standard deviation. This is done by taking the square root of the variance.

Standard Deviation = sqrt(5) ≈ 2.24 (rounded to two decimal places)

Therefore, the standard deviation of the population is approximately 2.24. It seems there was an error in your calculation of the standard deviation as 21.0, which is significantly different from the correct answer.