a. write the complete hydrolysis equation of NaC2H3O2
b. identify the spectator ions
c. identify conjugate acid base pairs
C2H3O2- + H2O <-----> C2H3O2H + OH-
a. To write the complete hydrolysis equation of NaC2H3O2, we need to consider how it reacts with water (H2O). Sodium acetate (NaC2H3O2) is a salt that dissociates into its respective ions in water. The sodium ion (Na+) and the acetate ion (C2H3O2-) will react with water.
The hydrolysis equation can be written as follows:
NaC2H3O2 + H2O → NaOH + HC2H3O2
In this equation, the sodium acetate reacts with water to form sodium hydroxide (NaOH) and acetic acid (HC2H3O2).
b. Spectator ions are the ions that do not participate in the chemical reaction and remain unchanged. In the hydrolysis equation of NaC2H3O2, the sodium ion (Na+) is a spectator ion. It remains unchanged and does not take part in the reaction. Therefore, Na+ is the spectator ion in this case.
c. Conjugate acid-base pairs are formed when an acid donates a proton (H+) to form a base, and the base accepts the proton to form an acid. In the hydrolysis equation of NaC2H3O2, we can identify the following conjugate acid-base pairs:
1. Acetic acid (HC2H3O2) and its conjugate base, acetate ion (C2H3O2-)
- HC2H3O2 donates a proton (H+) to form C2H3O2-
2. Water (H2O) and its conjugate acid, hydronium ion (H3O+)
- H2O accepts a proton (H+) to form H3O+ (hydronium ion)
These are the two conjugate acid-base pairs involved in the hydrolysis of NaC2H3O2.