An object initially at a temperature of 80 C cools by 1 C in a time of 15 s when placed in a 20 C room
When the object's temperature reaches 50 C, what is the average rate at which the object cools?
To calculate the average rate at which the object cools, we need to find the change in temperature and divide it by the change in time.
Given that the object initially at a temperature of 80°C cools by 1°C in a time of 15s, we can determine the rate at which it cools. The change in temperature is 80°C - 50°C = 30°C. The change in time is 15s.
Therefore, the average rate at which the object cools is calculated by dividing the change in temperature by the change in time:
Rate of cooling = (Change in temperature)/(Change in time)
= 30°C / 15s
= 2°C/s
So, the average rate at which the object cools when its temperature reaches 50°C is 2°C/s.