At a certain location, the solar power per unit area reaching the Earth's surface is 180 W/m2 averaged over a 24-hour day. Suppose you live in a solar powered house whose average power requirement is 3.2 kW.

At what rate must solar energy reach your solar panels if your solar panels have a typical coversion efficiency of 14 %. (In other words, what power must your solar panels receive?) Answer in both kiloWatts and Watts.

To find the rate at which solar energy must reach your solar panels, we can use the following formula:

Power = Area x Solar Power per unit area x Conversion Efficiency

Given information:
Solar power per unit area = 180 W/m^2
Conversion efficiency = 14%
Power requirement = 3.2 kW

First, we need to convert the power requirement from kilowatts to watts:
3.2 kW = 3,200 W

Let's assume the area of your solar panels is A square meters.

Using the formula, we can express the power requirement as:
3,200 W = A x 180 W/m^2 x 14%

Now, let's solve for A:
A = (3,200 W) / (180 W/m^2 x 14%)

A = (3,200 W) / (0.14 x 180 W/m^2)

A = (3,200 W) / (25.2 W/m^2)

A = 126.98 m^2

Therefore, the rate at which solar energy must reach your solar panels is approximately 126.98 m^2.

Converting this to kilowatts:
Power = Area x Solar Power per unit area x Conversion Efficiency
Power = 126.98 m^2 x 180 W/m^2 x 14% = 4567.9 W

Therefore, the power that your solar panels must receive is approximately 4.57 kW.

To determine the rate at which solar energy must reach your solar panels, we can follow these steps:

Step 1: Calculate the total energy requirement:
The average power requirement for your house is given as 3.2 kW (kiloWatts). We'll convert this into Watts by multiplying it by 1000:
3.2 kW * 1000 = 3200 W (Watts)

Step 2: Calculate the total energy received from the Sun (before conversion efficiency):
The solar power reaching the Earth's surface is given as 180 W/m² (Watts per square meter). We can calculate the total energy received from the Sun on an average 24-hour day by multiplying this power by the area of the solar panels.
We don't have the information about the area of your solar panels, so we'll assume a standard value (e.g., 10 m²) for this calculation:
180 W/m² * 10 m² = 1800 W (Watts)

Step 3: Account for the conversion efficiency of the solar panels:
The typical conversion efficiency of your solar panels is stated as 14%. To determine the power that your solar panels must receive, we need to divide the total energy requirement by the conversion efficiency:
3200 W / (14/100) = 3200 W / 0.14 ≈ 22,857.14 W

So, the power that your solar panels must receive is approximately 22,857.14 Watts or 22.9 kW (rounded to one decimal place).

Therefore, the solar panels must receive a power of 22.9 kW or 22,857.14 W to meet the average power requirement of your solar powered house, accounting for a typical conversion efficiency of 14%.

A)3.2kW/14*100 =22.85kW

B)22.85*1000=22857W