Posted by **Ben** on Sunday, March 27, 2011 at 9:29pm.

A particle with a mass of 2.0×10−5 kg and a charge of +2.0 microC is released in a (parallel plate) uniform horizontal electric field of 13 N/C. If the plates are 5.6 cm on each side, how much charge is on each? (in pC)

From what I have so far, the formula E=(4piKQ)/A; E=12 N/C, K=9x10^9 (Nm^2)/C^2, A=(0.056m)^2.

Whenever I plug this into my calculator, the answer I get for Q=3.6x10^-13 C, and the final answer to be 3.6x10^-22 pC.

Am I doing the arithmetic wrong? Any help would be greatly appreciated.

## Answer this Question

## Related Questions

- physics - Two parallel plates, separated by 10 mm, are charged to a potential ...
- Science - Use the following values for mass and charge: an electron has mass me...
- Science - Use the following values for mass and charge: an electron has mass me...
- Physics - An electromagnetic wave has an electric field strength of 145 V/m at a...
- physics - An electromagnetic wave has an electric field strength of 145 V/m at a...
- Physics - A parallel plate air capacitor of capacitance 245pF has a charge of ...
- physics parallel plate - A proton traveling at a speed 1.0*106 m/s of enters the...
- Physics - A parallel plate capacitor has a rectangular plates with length 5cm ...
- Physics - Two parallel plates are 4.85 cm apart. The bottom plate is charged ...
- physics help! - An electron enters the region of a uniform electric field ...