Posted by
**Ben** on
.

A particle with a mass of 2.0×10−5 kg and a charge of +2.0 microC is released in a (parallel plate) uniform horizontal electric field of 13 N/C. If the plates are 5.6 cm on each side, how much charge is on each? (in pC)

From what I have so far, the formula E=(4piKQ)/A; E=12 N/C, K=9x10^9 (Nm^2)/C^2, A=(0.056m)^2.

Whenever I plug this into my calculator, the answer I get for Q=3.6x10^-13 C, and the final answer to be 3.6x10^-22 pC.

Am I doing the arithmetic wrong? Any help would be greatly appreciated.