Homework Help: math

Posted by Dan on Sunday, March 27, 2011 at 3:57pm.

Consider the polynomial x^3 + 6x^2 + 3x - 10. Without dividing, or graphing, which two of (x+2), (x-2), (x+1), and (x-1) must be factors of the polynomial? Why/how do you know?

math - Damon, Sunday, March 27, 2011 at 5:06pm
I will need a 5 and a 2 to make 10
I need 2+5-1 to make 6 x^2
that leaves a (x+2)(x+5)(x-1)
so I think
(x+2) and (x-1)

Answer this Question

Related Questions

math - 3x-4=-2(3x+5) 3x-4=-2(3x+5) clear the fraction. 3x-4=-6x-10 add+6x+4 to ...
*re-Calc - I am trying to get the polynomial; x^7+2x^6+3x^5+4x^4+6x^3+6x^2+7x+8 ...
math - One of the following functions is neither odd nor even. Which one? x^5 + ...
pre-calc - I am trying to get the polynomial; x^7+2x^6+3x^5+4x^4+6x^3+6x^2+7x+8 ...
Math - Dividing a Polynomial - need detail and answer please!!! (6x^4+4x^3-x^2...
CP Algebra - 3x^2-6x-24 __________ 3x^2+2x-8 this is just simplifying ...
math - I need help graphing equations and inequalites like 5x+4y=20,6x-2y=-4,3x+...
calculus - Consider the graphs of y = 3x + c and y^2 = 6x, where c is a real ...
Math(Please check answers) - Factor completely. If the polynomial cannot be ...
Math- Adv. Alg. w/ Trig. - I need help simplifying this expression: (3x^3y^5 + ...

For Further Reading

First Name:
School Subject:
Answer: