7 (r+3s) - 2(2r -9s)
I am having a hard time solving can anyone please help
Multiply the # outside the parenthesis by each item inside the parenthesis to remove the parentesis and then combine the like terms (r's & s's).
7r + 21s - 4r + 18S
then combine like terms
7r +21s - 4r +18s
7r-4r =21s+18s
3r+39
Does this sound correct.
Yes , but 39s
Sure, I can help you solve the expression: 7(r+3s) - 2(2r - 9s).
To solve this expression, we need to follow the order of operations, which is often remembered using the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction).
Let's start by simplifying the expression inside the parentheses:
r + 3s
Next, we can distribute the 7 to each term inside the parentheses:
7r + 21s
Now, let's simplify the expression inside the second set of parentheses:
2r - 9s
Again, we can distribute the -2 to each term inside the parentheses:
-4r + 18s
Now, we can re-write the entire expression by adding the simplified terms together:
(7r + 21s) - (4r - 18s)
To remove the parentheses, we need to distribute the negative sign to each term inside the second set of parentheses:
7r + 21s - 4r + 18s
Now, we can combine like terms by adding or subtracting numbers with the same variables:
(7r - 4r) + (21s + 18s)
Simplifying further, we get:
3r + 39s
Therefore, the simplified form of 7(r+3s) - 2(2r - 9s) is 3r + 39s.
I hope this explanation helps you understand how to solve this expression.