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April 16, 2014

April 16, 2014

Posted by **tobi** on Sunday, March 27, 2011 at 12:54pm.

- mathematics -
**MathMate - check question**, Sunday, March 27, 2011 at 2:13pmThere are two cases: WB and BW

P(WB)=(2/5)*(3/4)=3/10

P(BW)=(3/5)*(2/4)=3/10

Probability of choosing balls of different colours = 6/10=3/5.

Check:

For same colours

P(WW)=(2/5)*(1/4)=1/10

P(BB)=(3/5)*(2/5)=3/1

P(all)=10/10 OK.

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