Posted by Brandon on Saturday, March 26, 2011 at 11:08pm.
Drwls  totally confused me on how this problem is done. Can someone else help to solve this problem?
If two numbers are relatively prime, what is their LCM? Explain the reasoning and give 2 examples supporting the answer.

math  Ms. Sue, Saturday, March 26, 2011 at 11:15pm
Did you carefully read all the information in the web site he posted?

math  Lena, Saturday, March 26, 2011 at 11:16pm
If a number is prime then you know that it's a multiple of itself and the number 1.
Example: Multiples for 7 are 7 & 1
Example: Multiples for 23 are 23 and 1
If you wanted to find the the LCM of both it would have to be 23 x 7
Do you understand why? There is no number other than 1 that can divide into both.
If you had nonprime numbers like 4 and 2, their LCM would be 4 since 2x2=4 and 1x4=4.
I don't know if I'm doing a good job explaining this or if I'm confusing you more but I tried.

math  Lena, Saturday, March 26, 2011 at 11:17pm
The multiples of 7 are not 7 and 1, rather what I meant to say is that 1x7 =7, the multiples of 7 would be 7,14,21 ect. Sorry if that confused you. Same with the number 23.

math  Lena, Saturday, March 26, 2011 at 11:18pm
The factors for 7 are 1 and 7
The factors for 23 are 1 and 23

math  MathMate, Saturday, March 26, 2011 at 11:32pm
"Since they have no common prime factors between them other than one, the Least Common Multiple must contain all the prime factors of both, making it the product of the two numbers."
This is what drwls posted, and to me it is crystal clear... unless you did not read what he wrote, just scanning for numbers.
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