Posted by **anna** on Saturday, March 26, 2011 at 9:13pm.

Hi,

I can't figure out how to start this one. I know I need to figure out the proportions or something of that sort. Any help is greatly appreciated Thanks!

Calculate ƒ¢H for the reaction

NO(g) + O(g) ¨ NO2(g)

given the following:

NO(g) + O3(g) ¨ NO2(g) + O2(g)

ƒ¢H = -198.9 kJ

O3(g) ¨ 3/2 O2(g)

ƒ¢H = -142.3 kJ

O2(g) ¨ 2O(g)

ƒ¢H = 495.0 kJ

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