Posted by HELP!!!! on Saturday, March 26, 2011 at 3:59pm.
You should not have to ask this question. I am sure exactly how to do it is in your text book.
(a) alpha = change in speed (140)/change in time (27)
(b) Torque = I alpha = 23 * alpha
(c) A = 0 + 0 t + (1/2) alpha t^2
(d)and (e) work done = change in kinetic energy
= (1/2) I w^2
where w = alpha t = 27 alpha
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