physics
posted by please help me on .
Water is flowing in a pipe as depicted in the figure. As shown, p = 117 kPa, d = 4.67 cm, d' = 3.06 cm, v = 4.36 m/s, and h = 1.11 m. What pressure is indicated on the upper pressure gauge? Take y = 0 at the bottom of the left pipe so that the center of the left pipe is y1 = d/2.

Without the figure, I have no idea what the two diameters are, nor where the uppoer pressure gauge is located.
Use the continuity equation
V+d^2 = constant
to relate velocity to pipe diamter.
Then use the Bernoulli equation
(1/2)*(rho)^V^2 + P +(rho)*g*h = 0
to relate pressure (P) to velocity and height. rho is the density of water.