Posted by **ashyLerry** on Saturday, March 26, 2011 at 12:11am.

The 235-kg cart in the figure starts from rest and rolls with negligible friction. It is pulled by three ropes as shown. It moves 600. m horizontally. Find the final velocity of the cart.

F1 = 500N at 0 degree

F2 = 500N at 40.1 degree

F3 = 400N at 30 degree

- physics -
**Henry**, Sunday, March 27, 2011 at 6:41pm
X = hor. = 500 + 500cos40.1 + 400cos30,

X = 500 + 382.5 + 346.4 = 1229N.

Y = ver. = 500sin40.1 + 400sin30,

Y = 322.1 + 200 = 522.1N.

F^2 = X^2 + Y^2,

F^2 = (1229)^2 + (522)^2,

F^2 = 1,783,029.

F = 1335N. = Resultant force.

a = F / m = 1335 / 235 = 5.69m/s^2.

(Vf)^2 = Vo^2 + 2ad,

(Vf)^2 = 0 + 2*5.69*600 = 6828,

Vf = 82.6m/s.

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