posted by don on .
how far weill a six foot pole fall in .02 seconds
The center of gravity will fall
X = 0.02*Vo + (1/2)*(0.02)^2*32.2 feet
Vo is the initial velocity in feet second. You need to say what it is.
The length of the pole does not matter.
You need to say if the pole is freely falling (which is what I assumed), or resting on the ground at one end, and tipping over.