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April 21, 2015

April 21, 2015

Posted by **Anonymous** on Friday, March 25, 2011 at 7:08pm.

- calculus -
**Damon**, Friday, March 25, 2011 at 7:21pmIn other words determine the minimum surface area for the given volume.

V = pi r^2 h

so h = 125/(pi r^2)

A = pi r^2 + 2 pi r h

A = pi r^2 + 2 pi r(125/(pi r^2))

A= pi r^2 + 250/r

dA/dr = 0 at min = 2 pi r -250/r^2

so

2 pi r = 250/r^2

pi r^3 =125

pi^(1/3) r = 5

r = 5/pi^(1/3)

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