How many different four-digit number combinations are possible from the numbers 0-9?
number of different 4 digit number
= 9x10x10x10 = 9000
(we cannot start with a zero, thus only 9 choices for the lead number)
In my answer, I assumed that you can repeat a number
If each can be used only once, then
number of ways = 9x9x8x7 or 4536
To find the number of different four-digit number combinations possible from the numbers 0-9, we need to consider each digit's possible values.
Since there are 10 possible digits (0-9) for each of the four positions, the total number of combinations can be found using the concept of permutations.
First, we need to determine the number of choices for each position. In this case, each position can have any of the 10 digits available.
To calculate the total number of combinations, we multiply the number of choices at each position together.
So, the number of combinations is: 10 choices for the first position x 10 choices for the second position x 10 choices for the third position x 10 choices for the fourth position.
Mathematically, it can be written as 10 x 10 x 10 x 10 = 10,000.
Therefore, there are 10,000 different four-digit number combinations possible from the numbers 0-9.