Friday

March 27, 2015

March 27, 2015

Posted by **Claire** on Friday, March 25, 2011 at 3:18pm.

any help is much appricated

- maths -
**Reiny**, Friday, March 25, 2011 at 5:14pmthe hard part is to integrate the cos^2x

we know that cos 2x = 2cos^2x - 1

so replace the 2cos^2x with cos2x + 1

then

dy/dx = 1+2cos^2x

= 1 + cos2x + 1 = 2 + cos2x

then y = 2x + (1/2)sin2x + c

given: when x=0, y = 1

1 = 0 + sin0 + c

c = 1

y = 2x + (1/2)sin2x + 1

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