Tuesday

January 27, 2015

January 27, 2015

Posted by **Claire** on Friday, March 25, 2011 at 3:18pm.

any help is much appricated

- maths -
**Reiny**, Friday, March 25, 2011 at 5:14pmthe hard part is to integrate the cos^2x

we know that cos 2x = 2cos^2x - 1

so replace the 2cos^2x with cos2x + 1

then

dy/dx = 1+2cos^2x

= 1 + cos2x + 1 = 2 + cos2x

then y = 2x + (1/2)sin2x + c

given: when x=0, y = 1

1 = 0 + sin0 + c

c = 1

y = 2x + (1/2)sin2x + 1

**Answer this Question**

**Related Questions**

maths - Hi Looking for some guidance please, I need to find the initial-value ...

maths - give the solution of the initial-value problem dy/dx=(1+2cos^2(x))/y, (y...

maths - give the solution of the initial-value problem dx/dy=(1+2cos^2(x))/y, (y...

calculus - Please help find the solution to the initial value problem dy/dx=(1+...

math - I am having to find the value of y for the given values of x. I ...

maths - Can any one help with the following please: Solve the initial-value ...

Physics - *I am lost on a bunch of different problems, and this is one of them. ...

Physics - *I am lost on a bunch of different problems, and this is one of them. ...

Physics - *I am lost on a bunch of different problems, and this is one of them. ...

maths - An initial-value problem is given by the differential equation, f(x,y...