Wednesday

August 27, 2014

August 27, 2014

Posted by **Anonymous** on Friday, March 25, 2011 at 12:15pm.

f(x) = x + sin x (−2π ≤ x ≤ 2π)

- Calculus please help -
**MathMate**, Sunday, March 27, 2011 at 10:37amPoints of inflection are points on the curve where the curvature changes sign.

Since the sign of curvature is equal to the sign of the second derivative, so the points of inflection can be found to be where the second derivative changes sign.

For

f(x)=x+sin(x),

f'(x)=1+cos(x)

f"(x)=-sin(x)

Make a plot of -sin(x) and you should find that f"(x) changes sign at x=0,π and 2π.

The inflection points are therefore at __, __, and __ according to the definition.

- Calculus please help -
**maria**, Thursday, March 31, 2011 at 12:45amy=100 find the first and second derivative

**Related Questions**

Calculus - Determine the points of inflection of the function. f(x) = x + sin x...

Trigonometry - IM STUCK ON THESE :( 1. What is the equation for shifting the ...

Trigonometry - IM STUCK ON THESE :( 1. What is the equation for shifting the ...

calculus - In spherical coordinates, the inequalities 0≤ρ≤2, 3...

Pre Calculus - sec x = -2 , π ≤ x ≤ 3π Use a calculator to...

PreCalc - I'm not sure how to solve these with calculator. sec x = -2 , π...

calculus - A particle moves on the x-axis so that its velocity at any time t is ...

Trig - On the same set of axes, sketch and label the graphs of the equations y...

Math - If y = sin−1 x, then sin y = x,−π/2 ≤ y ≤ &#...

Advanced Functions/Precalculus - Trigonometry Questions 1. Solve the equation ...