Post a New Question

algebra investments

posted by on .

Peter invested some money at 6% annual interest and martha invested some at 12%. If their investments is $6000 and their combined interest was $540. How much money did martha invest?

  • algebra investments - ,

    Let Peter's investment be x
    then Martha's investment is 6000-x

    solve:

    .06x + .12(6000-x) = 540
    6x + 12x(6000-x) = 54000

    I am sure you can finish it.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question