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September 15, 2014

September 15, 2014

Posted by **STEPHANIE** on Friday, March 25, 2011 at 12:44am.

HOW DO I FIND THE SOLUTION TO THIS PROBLEM?

- MATH -
**Reiny**, Friday, March 25, 2011 at 9:00amProb(blue eyes) = .2

Prob(not blue eyes)= .8

prob( at least 4 of 5 have blue eyes)

= prob(exactly 4 of 5 have blue eyes) + prob(exactly 5 of 5 have blue eyes)

= C(5,4)(.2)^4 (.8) + C(5,5)(.2)^5

= 5(.0016)(.8) + 1(.00032)

= .000672

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