Posted by **Eunice** on Thursday, March 24, 2011 at 5:56pm.

A movie theater charges $7 for adults, $5 for school-age children, and $3 for babies. A group of people went to the theater. There were the same number of school-age children as babies and the number of adults was the same as school-age children and babies combined. If the group paid $1562, how many babies were in the group ?

- Math - assistance needed -
**Writeacher**, Thursday, March 24, 2011 at 5:57pm
Please type your __subject__ in the **School Subject** box. Any other words, __including obscure abbreviations__, are likely to delay responses from a teacher who knows that subject well.

- Chicago Virtual Charter School -
**TutorCat**, Thursday, March 24, 2011 at 6:25pm
same number of school-age children as babies

x=number of school-age children

x=number of babies

number of adults was the same as school-age children and babies combined

y=number of adults

y=x+x

y=2x

$7(2x) + $5(x)+ $3(x) = $1562

similar problem - look at example 1:

http://www.algebra-class.com/algebra-word-problems.html

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