Posted by Sally on Thursday, March 24, 2011 at 2:13pm.
Please irnore the multiple choice answers-they were for a different problem that I copied down
find total resistance of the parallel network. I assume you mean ohms, not watts on the reistors.
1/Rt=1/4+1/6+1/10=1/60 (15+10+6)=31/60
Rt=60/31
Now add that inseries to 2 ohm, or total resistance is 151/60
current= V/R=12(60/151) check that
now, having total current, how does it divide in the paralel branch.
the voltage across the parallel branch is Rt*It= 60/131*69/151)
so current in each resistor is that voltage divided by either 4,6, or 10 ohms
Thank you for your help-I can really use the explanation for my other problems too.
Thank you again-
I have another question-I looked closely at the explanation and when you added the three resistors together you came up with Rt=60/31. Then you added the series to the 2Ohm and said total equals 151/60-I'm lost there because 2 Ohms would equal 30/60 or when added to the inseries it would become resistance total = 60/61 so where does the 151/60 come from? Sorry if I'm just not understanding
I figured it out-thank you
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