An equilibrium mixture contains 2.0cm 3 of 1.00mol dm-3 of h2so4. Calculate the number of moles of H+ in this acid???
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To calculate the number of moles of H+ in the given acid, we need to use the balanced equation for the dissociation of sulfuric acid (H2SO4). In the equation, each molecule of H2SO4 dissociates into 2 H+ ions.
The given information is:
- Volume of H2SO4 solution = 2.0 cm^3
- Concentration of H2SO4 = 1.00 mol dm^-3
Step 1: Convert Volume to Volume in dm^3
1 cm^3 is equal to 1 × 10^-3 dm^3. Therefore, 2.0 cm^3 is equal to 2.0 × 10^-3 dm^3.
Step 2: Calculate the Number of Moles
The number of moles can be calculated using the formula:
moles = concentration × volume in dm^3
moles = 1.00 mol dm^-3 × 2.0 × 10^-3 dm^3
moles = 2.0 × 10^-3 mol
Step 3: Multiply the Number of Moles by the Stoichiometric Coefficient
Since each molecule of H2SO4 dissociates into 2 H+ ions, the number of moles of H+ can be calculated by multiplying the number of moles of H2SO4 by 2.
moles of H+ = 2 × 2.0 × 10^-3 mol
moles of H+ = 4.0 × 10^-3 mol
Therefore, there are 4.0 × 10^-3 moles of H+ in the given acid.