Posted by Trace on Wednesday, March 23, 2011 at 11:22pm.
You are on the right track but do not appear to be solving for the separation distance of the galaxies from each other. Call that x. That is what they are asking for.
1.22 (lambda)/D = x/R
where R is 10 million light years
lambda = 400*10^-9 m
D = 2.4 m
Solve for x.
If you leave both x and R in light years, you can solve for x in light years.
x/R = 2.03*10^-7 (a dimensionless ratio)
x = 203 light years (when the light was emitted 10 billion light years ago)
My prof says that the answer should be of magnitude 10^19. I'm not sure what he's doing differently. Is there another way to solve this?
My prof says that the answer should be of magnitude 10^19. I'm not sure what he's doing differently. Is there another way to solve this?
I tried to get help from a friend, but her email just said to use tan theta = x/D. I'm not sure why she said to use tan theta, and when I do that-> tan 0.00001165*2.4m=x I get x= 0.000000487 which is obviously not right.
Related Questions
Physics - A telescope with a small circular aperture of diameter 2.0 centimeters...
physics - The Hubble Space Telescope orbits Earth 621 km above Earth's ...
Science - I need to now in order which of these are big in order from biggest to...
Astronomy (algebra-based physics) - Extrasolar planets There are currently 340 ...
physics - Two stars are 3.80 1011 m apart and are equally distant from the earth...
geometry - The Hubble Space Telescope is orbiting Earth 600 km above Earth's...
Physics - the hubble telescope has a mass of 1.5 x 10^4 kg and its orbiting the ...
Science - What are the disadvantages of Hubble Space Telescope?
Physics - The Hubble Space Telescope orbits the Earth at an approximate altitude...
Physics - The Hubble Space Telescope orbits the Earth at an approximate altitude...
For Further Reading