Math
posted by Ralph on .
given the fonction: y=3x^25x and x=g(t)derivable as g(14)=4 and g'(14)=2
calculate dy/dt in t = 14

y = 3x^2  5x
= 3(g(t)^2  5g(t)
dy/dt = 6 g(t) d(g(t))/dt  5 d(g(t))/dt
= 6(g(14)) d(g(14))/dt  5 d(g(14))/dt
= 6(4)(2)  5(2)
= 58