Posted by **Anonymous** on Wednesday, March 23, 2011 at 9:02pm.

a rancher wants to use 300 feet of fencing to enclose a rectangular area of 4400 square feet. what dimensions should the rectangle have?

- math 099 -
**Reiny**, Wednesday, March 23, 2011 at 10:26pm
length = x

width = y

x+y = 150 , y = 150-x

xy = 4400

x(150-x) = 4400

expanding and simplifying...

x^2 - 150x + 4400 = 0

(x-110)(x-40) = 0

x = 110 or x=40

if x=110, then y = 40

if x = 40, then y = 110

the dimenstions should be 110 ft by 40 ft

check: 2(110+40) = 300

(110)(40) = 4400

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