Posted by **Anonymous** on Wednesday, March 23, 2011 at 9:02pm.

a rancher wants to use 300 feet of fencing to enclose a rectangular area of 4400 square feet. what dimensions should the rectangle have?

- math 099 -
**Reiny**, Wednesday, March 23, 2011 at 10:26pm
length = x

width = y

x+y = 150 , y = 150-x

xy = 4400

x(150-x) = 4400

expanding and simplifying...

x^2 - 150x + 4400 = 0

(x-110)(x-40) = 0

x = 110 or x=40

if x=110, then y = 40

if x = 40, then y = 110

the dimenstions should be 110 ft by 40 ft

check: 2(110+40) = 300

(110)(40) = 4400

## Answer This Question

## Related Questions

- Math - A rancher has 220 feet of fencing to enclose a rectangular corral. Find ...
- College Algebra - Rita has 88 feet of fencing. She wants to use this fencing to ...
- Math - Corinda has 400 feet of square fencing to make a play area. She wants the...
- Math - 1. A man has 22 feet by 26 feet rectangular lot that he will use for ...
- Algebra - A rancher wishes to enclose a rectangular partitioned corral with 1932...
- College Algebra - A rancher wishes to enclose a rectangular partitioned corral ...
- Calculus - A rancher wants to make an animal pen by fencing in an area of ...
- College Algebra - A rancher has 100 meters of fencing to enclose two adjacent ...
- math - A rancher has 296 feet of fencing to enclose two adjacent rectangular ...
- Precalculus - a farmer has available 1032 feet of fencing and wishes to enclose ...

More Related Questions