Posted by C on Wednesday, March 23, 2011 at 8:22pm.
Let's start with b, the answer of which is correct: it is not invertible.
Domain of the function is ℝ since it is the exponential function raised to a polynomial power.
If it were invertible, as you mentioned, the derivative would not change sign.
Change in sign of the derivative implies that on each side of the extremum, the function will take on the same value within its domain, which renders the function not invertible. In other words, it does not pass the horizontal line test.
For part a.
Again, we have to first determine the domain of the function:
Since log functions cannot take on negative values, we determine that the domain of the function is limited to the range of x where the expression inside the log is non-negative, namely (-&infin,-1)∪(0,∞).
Now we have to look at the function within its domain.
We find that the function is monotonically decreasing throughout its domain, within which it satisfies the horizontal line test.
Would you therefore re-evaluate your answer?
To help make your decision, you can have some thoughts on two things:
1. look at the graph of the function:
http://img853.imageshack.us/i/1300926177.png/
2. Find its inverse:
f-1(x)=1/(10^x-1)
which is a perfectly legitimate function undefined at x=0.
Related Questions
Calc. checking answer - Determine whether or not each of the following functions...
LINEAR ALGEBRA - How to prove or disprove (a)if A has a zeronentryonthe diagonal...
College Math : Linear Algebra - Suppose A is a square matrix satisfying the ...
Algebra - Let A and B be n x n matrices, assume AB is invertible and show that ...
Math - Determine whether each of the following function is invertible and very ...
linear algebra - 1)If A is an invertible matrix and k is a positive integer, ...
Trig - Let f and g be two invertible functions such that f^-1(x)=5/x+4 and g(x)=...
math - If A^TA is an invertible matrix, prove that the column vectors of A are ...
Calculus - The figure is an invertible function . Use the figure to find the ...
Algebra - Right now we are learning about functions, relations, etc. and I am ...
For Further Reading