Posted by sweety on Wednesday, March 23, 2011 at 7:12pm.
Analyze the radial distribution of the Hatom at the 2s state. How are the maxima
situated with respect to the minimum?
Is the “golden ratio” involved?

physics  drwls, Wednesday, March 23, 2011 at 7:55pm
The 2s orbital has a probability distribution function that is a function of r only.
There is a maximum at r = 0 and a zeroprobability node at r = 2 ao, where ao is the Bohr radius. There is a secondary sphericalshell relative maximum at r = 4 ao. In don't see where the "golden ratio" (1.618) is involved.
The probability distribution function of that state is
u^2(r) = [1/(32 pi)]*(1/ao)^3 *[(2 (r/ao)]^2 *exp(r/ao)
See if you can find a golden ratio in the min and max locations

physics (correction)  drwls, Thursday, March 24, 2011 at 7:58am
The probability distribution function of that state is
u^2(r) = [1/(32 pi)]*(1/ao)^3 *[(2 (r/ao)]^2 *exp(r/ao)
Answer This Question
Related Questions
 chemistry  Analyze the radial distribution of the Hatom at the 2s state. How ...
 Science  Find examples of the golden ratio in nature  a minimum of 10 ...
 physics  The higher the energy level occupied by an electron in the hydrogen ...
 Physics  The higher the energy level occupied by an electron in the hydrogen ...
 Physics  The higher the energy level occupied by an electron in the hydrogen ...
 physics  The higher the energy level occupied by an electron in the hydrogen ...
 Physics  Can someone help me with this, i have started it but cant get it to ...
 Physics  Could someone help me with these questions. . . please 1. How does ...
 Calculus  Find the values of x that give relative extrema for the function f(x...
 algebra  the ancient greeks thought that the most pleasing shape for a ...
More Related Questions