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April 24, 2014

April 24, 2014

Posted by **NY-Calc** on Wednesday, March 23, 2011 at 1:45pm.

lim as x approaches (pi/2) e^(tanx)

I have the answer to be zero:

t = tanx

lim as t approaches negative infi e^t

= 0

Why is tan (pi/2) approaching negative infinity is my question?

- Calculus -
**Damon**, Wednesday, March 23, 2011 at 3:09pmtan x = sin x / cos x

as x-->pi/2

sin x --> +1 and cos x-->0

cos goes to +0 from the first quadrant and cos goes to -0 from the second quadrant as x-->pi/2

so depending on if you approach pi/2 from right or from left, tan x -->__+oo or -oo

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