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March 27, 2017

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In 2010 a city raised $5,999,400 in tax revenue by charging each taxpayer the same amount. For 2011 there has been a net loss of 12 taxpayers, necessitating an increase fo $200 per taxpayer in order to maintain the tax revenue of $5,999,400. How many taxpayers were there in 2010?

  • math - ,

    X-Taxpayers in 2010.

    (X - 12)Taxpayers in 2011.

    $200(X - 12) = $5,999,400.
    X - 12 = 29997 Taxpayers in 2011.

  • math - ,

    X - 12 = 29997,
    X = 30009 Taxpayers in 2010.

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