Posted by **John** on Wednesday, March 23, 2011 at 10:56am.

In 2010 a city raised $5,999,400 in tax revenue by charging each taxpayer the same amount. For 2011 there has been a net loss of 12 taxpayers, necessitating an increase fo $200 per taxpayer in order to maintain the tax revenue of $5,999,400. How many taxpayers were there in 2010?

- math -
**Henry**, Friday, March 25, 2011 at 10:26pm
X-Taxpayers in 2010.

(X - 12)Taxpayers in 2011.

$200(X - 12) = $5,999,400.

X - 12 = 29997 Taxpayers in 2011.

- math -
**Henry**, Friday, March 25, 2011 at 10:32pm
X - 12 = 29997,

X = 30009 Taxpayers in 2010.

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