Monday

September 15, 2014

September 15, 2014

Posted by **Lisa** on Wednesday, March 23, 2011 at 4:22am.

I'm confused about how to solve this problem. Could someone show me the steps?

- Math -
**Henry**, Friday, March 25, 2011 at 9:40pmX = hor = 19km.

Y = ver = -32km.

d^2 = X^2 + Y^2,

d^2 = (19)^2 + (-32)^2,

d^2 = 361 + 1024 = 1385,

d = 37.2km.

tanA = Y/X = -32/19 = -1.6842,

A = -59.3deg,CW=360 - 59.3 = 300.7deg CCW=300.7 - 270=30.7deg East of South.

**Answer this Question**

**Related Questions**

Math - A boat in calm seas travels 19 km east and 32 km south. Find the distance...

math - A boat in calm seas travels 13km east and 35 km north. Find the distance ...

Physics - A current of a river flows steadily from west to east at 1.00 m/s. A ...

Physics - A jogger travels a route that has two parts. The first is a ...

Physics - Canadian geese migrate essentially along a north-south direction for ...

physics - Search: On a pleasure cruise a boat is traveling relative to the water...

physics - On a pleasure cruise a boat is traveling relative to the water at a ...

Physics - A jogger travels a route that has two parts. The first is a ...

physics - A jogger travels a route that has two parts. The first is a ...

Physics - A jogger travels a route that has two parts. The first is a ...