Post a New Question

chemistry

posted by .

2.00 L of NO(g) at 1.00 atm and 25°C is reacted with 1.00 L of H2(g) at 2.00 atm and 25°C according to the following unbalanced equation.
NO(g) + H2(g) ® N2(g) + H2O(g)
Which, if either, is the limiting reactant?

  • chemistry -

    When all are gaseous, one may use L as if L = moles, a good short cut to remember. Second, we must make sure both are at the same pressure; that can be accomplished by changing H2 to 1.00 atm. 1L H2 @ 2.00 atm = 2 L H2 @ 1.00 atm.
    2NO(g) + 2H2(g) ® N2(g) + 2H2O(g)

    Use the coefficients in the balanced equation to convert L NO and L H2 to L of either of the products.
    2L NO x (1 mole N2/2 mols NO) = 2(1/2) = 1 mole N2 formed.

    2L H2 X (1 mole N2/2 moles H2) = 2(1/2) = 1 mol N2 produced.
    Therefore, neither is the limiting reagent. Or we could say both are limiting reagents.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question