When 2.6 ×103 g of CaCO3 are heated, the
actual yield of CaO is 1.06 ×103 g. What is the percent yield?
Answer in units of %.
To calculate the percent yield, we need to know the theoretical yield and the actual yield. The theoretical yield is the amount of product that would be obtained if the reaction proceeded perfectly according to the balanced chemical equation.
In this case, the balanced equation for the reaction is:
CaCO3 → CaO + CO2
From the equation, we can see that the molar ratio between CaCO3 and CaO is 1:1. This means that for every 1 mole of CaCO3, we should obtain 1 mole of CaO.
To calculate the theoretical yield of CaO, we need to convert the mass of CaCO3 to moles using the molar mass of CaCO3:
molar mass of CaCO3 = 40.08 g/mol (Ca) + 12.01 g/mol (C) + (3 * 16.00 g/mol) (O) = 100.09 g/mol
moles of CaCO3 = mass of CaCO3 / molar mass of CaCO3
moles of CaCO3 = 2.6 × 10^3 g / 100.09 g/mol = 25.97 mol
Since the molar ratio between CaCO3 and CaO is 1:1, the theoretical yield of CaO is also 25.97 mol.
Now we can calculate the percent yield using the formula:
percent yield = (actual yield / theoretical yield) * 100
actual yield = 1.06 × 10^3 g
theoretical yield = 25.97 mol
To calculate the actual yield in moles, we need to convert the mass of CaO to moles using the molar mass of CaO:
molar mass of CaO = 40.08 g/mol (Ca) + 16.00 g/mol (O) = 56.08 g/mol
moles of CaO = mass of CaO / molar mass of CaO
moles of CaO = 1.06 × 10^3 g / 56.08 g/mol = 18.92 mol
Now we can plug the values into the formula to calculate the percent yield:
percent yield = (18.92 mol / 25.97 mol) * 100 = 72.9%
Therefore, the percent yield is 72.9%.