What is the height of a triangle whose base is 9.4 centimeters and whose area is 132.54 square centimeters?
Area=(1/2)*base*hight
A=(b*h)/2
A=Area=132.54cm^2
b=base=9.4cm
h=hight
A=(b*h)/2
132.54=(9.4*h)/2 Multiply with 2
265.08=9.4*h Divide with 9.4
h=265.08/9.4
h=28.2 cm
To find the height of a triangle, given its base and area, we can use the formula:
Area = (base × height) / 2
Let's plug in the values we know into this formula:
132.54 = (9.4 × height) / 2
To solve for the height, we first multiply both sides by 2 to get rid of the fraction:
132.54 × 2 = 9.4 × height
265.08 = 9.4 × height
Next, we divide both sides by 9.4 to isolate the height:
265.08 / 9.4 = height
Simplifying this equation:
height ≈ 28.23 centimeters
Therefore, the height of the triangle is approximately 28.23 centimeters.
To find the height of a triangle, you can use the formula for the area of a triangle which is given by:
Area = (1/2) * base * height
In this case, you are given the base of the triangle (9.4 centimeters) and the area (132.54 square centimeters). You can rearrange the formula to solve for the height:
height = (2 * Area) / base
Substituting the given values:
height = (2 * 132.54) / 9.4
height = 265.08 / 9.4
height = 28.25 centimeters
Therefore, the height of the triangle is 28.25 centimeters.