What is the height of a triangle whose base is 9.4 centimeters and whose area is 132.54 square centimeters?

Area=(1/2)*base*hight

A=(b*h)/2

A=Area=132.54cm^2

b=base=9.4cm

h=hight

A=(b*h)/2

132.54=(9.4*h)/2 Multiply with 2

265.08=9.4*h Divide with 9.4

h=265.08/9.4

h=28.2 cm

To find the height of a triangle, given its base and area, we can use the formula:

Area = (base × height) / 2

Let's plug in the values we know into this formula:

132.54 = (9.4 × height) / 2

To solve for the height, we first multiply both sides by 2 to get rid of the fraction:

132.54 × 2 = 9.4 × height

265.08 = 9.4 × height

Next, we divide both sides by 9.4 to isolate the height:

265.08 / 9.4 = height

Simplifying this equation:

height ≈ 28.23 centimeters

Therefore, the height of the triangle is approximately 28.23 centimeters.

To find the height of a triangle, you can use the formula for the area of a triangle which is given by:

Area = (1/2) * base * height

In this case, you are given the base of the triangle (9.4 centimeters) and the area (132.54 square centimeters). You can rearrange the formula to solve for the height:

height = (2 * Area) / base

Substituting the given values:

height = (2 * 132.54) / 9.4
height = 265.08 / 9.4
height = 28.25 centimeters

Therefore, the height of the triangle is 28.25 centimeters.