Posted by Anonymous on .
Data shows that 88% of the people in a certain population are righthanded. A group of 7 people from this population are selected at random.
(a) What would be the expected value for the number of righthanded people in the group?
(b) What is the probability that exactly 5 of the people in the group are righthanded?
(c) What is the probability that at least 5 of the people in the group are righthanded?

statistics 
MathGuru,
(a) Take sample size times .88 for expected value.
(b) Use a binomial probability table. Values are: n = 7, x = 5, and p = .88
(c) Use the table again. Find x = 5,6,7. Use same values for n and p. Add together for total probability.
I hope this will help get you started.