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March 26, 2017

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A cannon of mass 200kg, fires a cannonball with a mass of 10kg. The cannon ball leaves the barrel of the cannon with a velocity of 60 m/s. Using the law of conservation of momentum , explain what happens to the cannon when the cannon ball is fired. (Answer should include calculation.)

  • Physics - ,

    Well, I guess this cannon is fired horizontally.

    final momentum = 200 v + 10 *60 = initial momentum = 0
    so
    v = - 600/200 = -3 m/s

  • Physics - ,

    Why is it 200v ??Is the formula used :
    m1v2+m2v2=(m1+m2)v ???

    Confusedd

  • Physics - ,

    Pbefore = Pafter
    (m1v2)+(m2v2) = (m1v2)+(m2v2)

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