I have an electrical circuit which has 20V shown on left side
I=0.8A on top
I = 0.3A on bottom
I have to find the resistance
Would I add 0.8 + 0.3 and then use the formula V = IR
so it would look like this:
20V = 1.1A x R
20V x 1.1A = R
I am a little puzzled by your description of the circuit.
However if two different currents are flowing through the resistors then they must be in parallel in which case each sees 20 volts
R1 = 20/.8
R2 = 20/.3
You add resistances that are in series. Then each has the same current and the voltage is split.
now if you want the equivalent resistance of the whole circuit it is the voltage divided by the entire current
Req = 20/(1.1)
by the way
1 / Req = 1/R1 + 1/R2
1/Req = .8/20 + .3/20 = 1.1/20
so
Req = 20/1.1 which we already knew
Thank you for all your explanations-it really helped alot
To find the resistance, you need to use Ohm's Law, which states that V (voltage) is equal to I (current) multiplied by R (resistance).
If you want to find the resistance, you should rearrange the formula as follows:
R = V/I
In your case, you have a total current of I = 0.8A + 0.3A = 1.1A. So the formula becomes:
R = 20V / 1.1A
To calculate the resistance, simply divide the voltage by the current:
R = 18.18 Ω (rounded to two decimal places)
So, the resistance of the circuit is approximately 18.18 ohms.