Write a program that inputs a word representing a binary number (0s and 1s). First, your program should verify that it is indeed a binary number, that is, the number contains only 0s and 1s. if that is not the case, your program should print a message that the number is not a valid binary number. Then, your program should count how many 1s are in that word and output the count.

What part are you stuck on?

10001

Sure! Here's a Python program that can accomplish this task:

```python
def count_ones(binary_number):
# Verify if it is a valid binary number
if set(binary_number) - {'0', '1'}:
print("The number is not a valid binary number.")
return

# Count the number of 1s
count = binary_number.count('1')

# Print the count
print(f"The number of 1s in the binary number is {count}.")

# Take user input for the binary number
binary_number = input("Enter a binary number: ")

# Call the function to count the number of 1s
count_ones(binary_number)
```

Here's how you can get the answer manually if you don't want to use the program:

1. Verify if the given number is a valid binary number. To do this, check if the number contains only 0's and 1's. If it contains any other digit, it is not a valid binary number. If it is not a valid binary number, print a message stating that.

2. If the number is a valid binary number, count the number of 1's in it. To do this, iterate through each digit of the binary number and keep a count of how many digits are equal to 1.

3. Once you have the count, print it as the output.