statistics
posted by mark on .
Data shows that 93% of the people in a certain population are righthanded. A group of 9 people from this population are selected at random. What is the probability that exactly 7 of the people in the group are righthanded?
2

prob of righthanded = .93
prob of NOT righthanded = .07
prob (7 of 9 are righthanded)
= C(9,7)(.93)^7(.07)^2
= appr. 0.10614