physics
posted by duke on .
A cannon tilted up at a 26.0 degree angle fires a cannon ball at 78.0 m/s from atop a 12.0 mhigh fortress wall. What is the ball's impact speed on the ground below?

u = constant horizontal speed = 78 cos 26
Vi = initial up speed = 78 sin 26
v = Vi  g t
h = 12 + Vi t  4.9 t^2
at ground, h = 0
4.9 t^2 Vi t  12 = 0
solve for t, time in air
then use that t so solve for v at t in v=Vi 9.8 t
then impact speed = sqrt(u^2+v^2)